(X^2-22x-325)=0

Solution for (X^2-22x-325)=0 equation:

(X^2-22X-325)=0

We get rid of parentheses

X^2-22X-325=0

a = 1; b = -22; c = -325;
Δ = b2-4ac
Δ = -222-4·1·(-325)
Δ = 1784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1784}=\sqrt{4*446}=\sqrt{4}*\sqrt{446}=2\sqrt{446}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2\sqrt{446}}{2*1}=\frac{22-2\sqrt{446}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2\sqrt{446}}{2*1}=\frac{22+2\sqrt{446}}{2}
$